(a^2)-3a-14=0

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Solution for (a^2)-3a-14=0 equation: 



(a^2)-3a-14=0

a = 1; b = -3; c = -14;
Δ = b2-4ac
Δ = -32-4·1·(-14)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{65}}{2*1}=\frac{3-\sqrt{65}}{2}
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{65}}{2*1}=\frac{3+\sqrt{65}}{2}
$

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